-8(b+3)-8(4b-3)=-6b+3b

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Solution for -8(b+3)-8(4b-3)=-6b+3b equation: 



-8(b+3)-8(4b-3)=-6b+3b

We move all terms to the left:

-8(b+3)-8(4b-3)-(-6b+3b)=0

We add all the numbers together, and all the variables

-8(b+3)-8(4b-3)-(-3b)=0

We multiply parentheses

-8b-32b-(-3b)-24+24=0

We get rid of parentheses

-8b-32b+3b-24+24=0

We add all the numbers together, and all the variables

-37b=0

b=0/-37

b=0

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