-8(c+1)=2(1-5c)+2

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Solution for -8(c+1)=2(1-5c)+2 equation:


Simplifying
-8(c + 1) = 2(1 + -5c) + 2

Reorder the terms:
-8(1 + c) = 2(1 + -5c) + 2
(1 * -8 + c * -8) = 2(1 + -5c) + 2
(-8 + -8c) = 2(1 + -5c) + 2
-8 + -8c = (1 * 2 + -5c * 2) + 2
-8 + -8c = (2 + -10c) + 2

Reorder the terms:
-8 + -8c = 2 + 2 + -10c

Combine like terms: 2 + 2 = 4
-8 + -8c = 4 + -10c

Solving
-8 + -8c = 4 + -10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '10c' to each side of the equation.
-8 + -8c + 10c = 4 + -10c + 10c

Combine like terms: -8c + 10c = 2c
-8 + 2c = 4 + -10c + 10c

Combine like terms: -10c + 10c = 0
-8 + 2c = 4 + 0
-8 + 2c = 4

Add '8' to each side of the equation.
-8 + 8 + 2c = 4 + 8

Combine like terms: -8 + 8 = 0
0 + 2c = 4 + 8
2c = 4 + 8

Combine like terms: 4 + 8 = 12
2c = 12

Divide each side by '2'.
c = 6

Simplifying
c = 6

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