-8(d+1)-d-9=-9(d+3)+10

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Solution for -8(d+1)-d-9=-9(d+3)+10 equation: 



-8(d+1)-d-9=-9(d+3)+10

We move all terms to the left:

-8(d+1)-d-9-(-9(d+3)+10)=0

We add all the numbers together, and all the variables

-1d-8(d+1)-(-9(d+3)+10)-9=0

We multiply parentheses

-1d-8d-(-9(d+3)+10)-8-9=0



We calculate terms in parentheses: -(-9(d+3)+10), so:

-9(d+3)+10

We multiply parentheses

-9d-27+10

We add all the numbers together, and all the variables

-9d-17

Back to the equation:

-(-9d-17)



We add all the numbers together, and all the variables

-9d-(-9d-17)-17=0

We get rid of parentheses

-9d+9d+17-17=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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