-8(d+2)-d-4=-9(d+4)+16

Solution for -8(d+2)-d-4=-9(d+4)+16 equation:

-8(d+2)-d-4=-9(d+4)+16

We move all terms to the left:

-8(d+2)-d-4-(-9(d+4)+16)=0

We add all the numbers together, and all the variables

-1d-8(d+2)-(-9(d+4)+16)-4=0

We multiply parentheses

-1d-8d-(-9(d+4)+16)-16-4=0


We calculate terms in parentheses: -(-9(d+4)+16), so:

-9(d+4)+16

We multiply parentheses

-9d-36+16

We add all the numbers together, and all the variables

-9d-20

Back to the equation:

-(-9d-20)


We add all the numbers together, and all the variables

-9d-(-9d-20)-20=0

We get rid of parentheses

-9d+9d+20-20=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0