-8(n-10)+n(1+4n)=-6

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Solution for -8(n-10)+n(1+4n)=-6 equation: 



-8(n-10)+n(1+4n)=-6

We move all terms to the left:

-8(n-10)+n(1+4n)-(-6)=0

We add all the numbers together, and all the variables

-8(n-10)+n(4n+1)-(-6)=0

We add all the numbers together, and all the variables

-8(n-10)+n(4n+1)+6=0

We multiply parentheses

4n^2-8n+n+80+6=0

We add all the numbers together, and all the variables

4n^2-7n+86=0

a = 4; b = -7; c = +86;
Δ = b2-4ac
Δ = -72-4·4·86
Δ = -1327
Delta is less than zero, so there is no solution for the equation

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