-8(x+1)+5(3x-4)=6(x-5)+12

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Solution for -8(x+1)+5(3x-4)=6(x-5)+12 equation: 



-8(x+1)+5(3x-4)=6(x-5)+12

We move all terms to the left:

-8(x+1)+5(3x-4)-(6(x-5)+12)=0

We multiply parentheses

-8x+15x-(6(x-5)+12)-8-20=0



We calculate terms in parentheses: -(6(x-5)+12), so:

6(x-5)+12

We multiply parentheses

6x-30+12

We add all the numbers together, and all the variables

6x-18

Back to the equation:

-(6x-18)



We add all the numbers together, and all the variables

7x-(6x-18)-28=0

We get rid of parentheses

7x-6x+18-28=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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