-8(x+2)=40-x

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Solution for -8(x+2)=40-x equation: 



-8(x+2)=40-x

We move all terms to the left:

-8(x+2)-(40-x)=0

We add all the numbers together, and all the variables

-8(x+2)-(-1x+40)=0

We multiply parentheses

-8x-(-1x+40)-16=0

We get rid of parentheses

-8x+1x-40-16=0

We add all the numbers together, and all the variables

-7x-56=0

We move all terms containing x to the left, all other terms to the right

-7x=56

x=56/-7

x=-8

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