-8(x+3)+3(4x-4)=3(x-3)+12

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Solution for -8(x+3)+3(4x-4)=3(x-3)+12 equation: 



-8(x+3)+3(4x-4)=3(x-3)+12

We move all terms to the left:

-8(x+3)+3(4x-4)-(3(x-3)+12)=0

We multiply parentheses

-8x+12x-(3(x-3)+12)-24-12=0



We calculate terms in parentheses: -(3(x-3)+12), so:

3(x-3)+12

We multiply parentheses

3x-9+12

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

4x-(3x+3)-36=0

We get rid of parentheses

4x-3x-3-36=0

We add all the numbers together, and all the variables

x-39=0

We move all terms containing x to the left, all other terms to the right

x=39

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