-8(x+3)=-6(3x-4)+6x

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Solution for -8(x+3)=-6(3x-4)+6x equation: 



-8(x+3)=-6(3x-4)+6x

We move all terms to the left:

-8(x+3)-(-6(3x-4)+6x)=0

We multiply parentheses

-8x-(-6(3x-4)+6x)-24=0



We calculate terms in parentheses: -(-6(3x-4)+6x), so:

-6(3x-4)+6x

We add all the numbers together, and all the variables

6x-6(3x-4)

We multiply parentheses

6x-18x+24

We add all the numbers together, and all the variables

-12x+24

Back to the equation:

-(-12x+24)



We get rid of parentheses

-8x+12x-24-24=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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