-8(x-4)-2=-3(-2+2x)-4

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Solution for -8(x-4)-2=-3(-2+2x)-4 equation: 



-8(x-4)-2=-3(-2+2x)-4

We move all terms to the left:

-8(x-4)-2-(-3(-2+2x)-4)=0

We add all the numbers together, and all the variables

-8(x-4)-(-3(2x-2)-4)-2=0

We multiply parentheses

-8x-(-3(2x-2)-4)+32-2=0



We calculate terms in parentheses: -(-3(2x-2)-4), so:

-3(2x-2)-4

We multiply parentheses

-6x+6-4

We add all the numbers together, and all the variables

-6x+2

Back to the equation:

-(-6x+2)



We add all the numbers together, and all the variables

-8x-(-6x+2)+30=0

We get rid of parentheses

-8x+6x-2+30=0

We add all the numbers together, and all the variables

-2x+28=0

We move all terms containing x to the left, all other terms to the right

-2x=-28

x=-28/-2

x=+14

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