-8(x-5)-8(3+3x)=48

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Solution for -8(x-5)-8(3+3x)=48 equation: 



-8(x-5)-8(3+3x)=48

We move all terms to the left:

-8(x-5)-8(3+3x)-(48)=0

We add all the numbers together, and all the variables

-8(x-5)-8(3x+3)-48=0

We multiply parentheses

-8x-24x+40-24-48=0

We add all the numbers together, and all the variables

-32x-32=0

We move all terms containing x to the left, all other terms to the right

-32x=32

x=32/-32

x=-1

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