-8(y+3)+4y+6=6y+12

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Solution for -8(y+3)+4y+6=6y+12 equation: 



-8(y+3)+4y+6=6y+12

We move all terms to the left:

-8(y+3)+4y+6-(6y+12)=0

We add all the numbers together, and all the variables

4y-8(y+3)-(6y+12)+6=0

We multiply parentheses

4y-8y-(6y+12)-24+6=0

We get rid of parentheses

4y-8y-6y-12-24+6=0

We add all the numbers together, and all the variables

-10y-30=0

We move all terms containing y to the left, all other terms to the right

-10y=30

y=30/-10

y=-3

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