-8(y-3)=6y+32

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Solution for -8(y-3)=6y+32 equation: 



-8(y-3)=6y+32

We move all terms to the left:

-8(y-3)-(6y+32)=0

We multiply parentheses

-8y-(6y+32)+24=0

We get rid of parentheses

-8y-6y-32+24=0

We add all the numbers together, and all the variables

-14y-8=0

We move all terms containing y to the left, all other terms to the right

-14y=8

y=8/-14

y=-4/7

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