-8(y-4)=-6y+48

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Solution for -8(y-4)=-6y+48 equation: 



-8(y-4)=-6y+48

We move all terms to the left:

-8(y-4)-(-6y+48)=0

We multiply parentheses

-8y-(-6y+48)+32=0

We get rid of parentheses

-8y+6y-48+32=0

We add all the numbers together, and all the variables

-2y-16=0

We move all terms containing y to the left, all other terms to the right

-2y=16

y=16/-2

y=-8

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