-8(y-6)=2y+28

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Solution for -8(y-6)=2y+28 equation:



-8(y-6)=2y+28
We move all terms to the left:
-8(y-6)-(2y+28)=0
We multiply parentheses
-8y-(2y+28)+48=0
We get rid of parentheses
-8y-2y-28+48=0
We add all the numbers together, and all the variables
-10y+20=0
We move all terms containing y to the left, all other terms to the right
-10y=-20
y=-20/-10
y=+2

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