-8(z+1)+5(3z-7)=6(z-5)=11

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Solution for -8(z+1)+5(3z-7)=6(z-5)=11 equation: 



-8(z+1)+5(3z-7)=6(z-5)=11

We move all terms to the left:

-8(z+1)+5(3z-7)-(6(z-5))=0

We multiply parentheses

-8z+15z-(6(z-5))-8-35=0



We calculate terms in parentheses: -(6(z-5)), so:

6(z-5)

We multiply parentheses

6z-30

Back to the equation:

-(6z-30)



We add all the numbers together, and all the variables

7z-(6z-30)-43=0

We get rid of parentheses

7z-6z+30-43=0

We add all the numbers together, and all the variables

z-13=0

We move all terms containing z to the left, all other terms to the right

z=13

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