-8(z+4)=-7(z+4)+-3

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Solution for -8(z+4)=-7(z+4)+-3 equation: 



-8(z+4)=-7(z+4)+-3

We move all terms to the left:

-8(z+4)-(-7(z+4)+-3)=0

We use the square of the difference formula

-8(z+4)-(-7(z+4)-3)=0

We multiply parentheses

-8z-(-7(z+4)-3)-32=0



We calculate terms in parentheses: -(-7(z+4)-3), so:

-7(z+4)-3

We multiply parentheses

-7z-28-3

We add all the numbers together, and all the variables

-7z-31

Back to the equation:

-(-7z-31)



We get rid of parentheses

-8z+7z+31-32=0

We add all the numbers together, and all the variables

-1z-1=0

We move all terms containing z to the left, all other terms to the right

-z=1

z=1/-1

z=-1

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