-8+13x2=0

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Solution for -8+13x2=0 equation:



-8+13x^2=0
a = 13; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·13·(-8)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{26}}{2*13}=\frac{0-4\sqrt{26}}{26} =-\frac{4\sqrt{26}}{26} =-\frac{2\sqrt{26}}{13} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{26}}{2*13}=\frac{0+4\sqrt{26}}{26} =\frac{4\sqrt{26}}{26} =\frac{2\sqrt{26}}{13} $

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