-8+2(4x+12)=4(1-3x)-13

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Solution for -8+2(4x+12)=4(1-3x)-13 equation: 



-8+2(4x+12)=4(1-3x)-13

We move all terms to the left:

-8+2(4x+12)-(4(1-3x)-13)=0

We add all the numbers together, and all the variables

2(4x+12)-(4(-3x+1)-13)-8=0

We multiply parentheses

8x-(4(-3x+1)-13)+24-8=0



We calculate terms in parentheses: -(4(-3x+1)-13), so:

4(-3x+1)-13

We multiply parentheses

-12x+4-13

We add all the numbers together, and all the variables

-12x-9

Back to the equation:

-(-12x-9)



We add all the numbers together, and all the variables

8x-(-12x-9)+16=0

We get rid of parentheses

8x+12x+9+16=0

We add all the numbers together, and all the variables

20x+25=0

We move all terms containing x to the left, all other terms to the right

20x=-25

x=-25/20

x=-1+1/4

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