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-8+2/3x+4=2x-5-4
We move all terms to the left:
-8+2/3x+4-(2x-5-4)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2/3x-(2x-9)-8+4=0
We add all the numbers together, and all the variables
2/3x-(2x-9)-4=0
We get rid of parentheses
2/3x-2x+9-4=0
We multiply all the terms by the denominator
-2x*3x+9*3x-4*3x+2=0
Wy multiply elements
-6x^2+27x-12x+2=0
We add all the numbers together, and all the variables
-6x^2+15x+2=0
a = -6; b = 15; c = +2;
Δ = b2-4ac
Δ = 152-4·(-6)·2
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{273}}{2*-6}=\frac{-15-\sqrt{273}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{273}}{2*-6}=\frac{-15+\sqrt{273}}{-12} $
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