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-8+5x=2(x-4)-8x
We move all terms to the left:
-8+5x-(2(x-4)-8x)=0
We calculate terms in parentheses: -(2(x-4)-8x), so:We get rid of parentheses
2(x-4)-8x
We add all the numbers together, and all the variables
-8x+2(x-4)
We multiply parentheses
-8x+2x-8
We add all the numbers together, and all the variables
-6x-8
Back to the equation:
-(-6x-8)
5x+6x+8-8=0
We add all the numbers together, and all the variables
11x=0
x=0/11
x=0
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