-8+6(v-11)=10v-2(1+8v)

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Solution for -8+6(v-11)=10v-2(1+8v) equation:



-8+6(v-11)=10v-2(1+8v)
We move all terms to the left:
-8+6(v-11)-(10v-2(1+8v))=0
We add all the numbers together, and all the variables
6(v-11)-(10v-2(8v+1))-8=0
We multiply parentheses
6v-(10v-2(8v+1))-66-8=0
We calculate terms in parentheses: -(10v-2(8v+1)), so:
10v-2(8v+1)
We multiply parentheses
10v-16v-2
We add all the numbers together, and all the variables
-6v-2
Back to the equation:
-(-6v-2)
We add all the numbers together, and all the variables
6v-(-6v-2)-74=0
We get rid of parentheses
6v+6v+2-74=0
We add all the numbers together, and all the variables
12v-72=0
We move all terms containing v to the left, all other terms to the right
12v=72
v=72/12
v=6

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