-8-3w+-39=(4w+44)7w

Solution for -8-3w+-39=(4w+44)7w equation:

-8-3w+-39=(4w+44)7w

We move all terms to the left:

-8-3w+-39-((4w+44)7w)=0

We add all the numbers together, and all the variables

-3w-((4w+44)7w)=0


We calculate terms in parentheses: -((4w+44)7w), so:

(4w+44)7w

We multiply parentheses

28w^2+308w

Back to the equation:

-(28w^2+308w)


We get rid of parentheses

-28w^2-3w-308w=0

We add all the numbers together, and all the variables

-28w^2-311w=0

a = -28; b = -311; c = 0;
Δ = b2-4ac
Δ = -3112-4·(-28)·0
Δ = 96721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{96721}=311$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-311)-311}{2*-28}=\frac{0}{-56}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-311)+311}{2*-28}=\frac{622}{-56}
=-11+3/28
$