-8/2x+6=-4/x+3

Solution for -8/2x+6=-4/x+3 equation:

-8/2x+6=-4/x+3

We move all terms to the left:

-8/2x+6-(-4/x+3)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x+3)!=0

x∈R


We get rid of parentheses

-8/2x+4/x-3+6=0

We calculate fractions


(-8x)/2x^2+8x/2x^2-3+6=0

We add all the numbers together, and all the variables

(-8x)/2x^2+8x/2x^2+3=0

We multiply all the terms by the denominator


(-8x)+8x+3*2x^2=0

We add all the numbers together, and all the variables

8x+(-8x)+3*2x^2=0

Wy multiply elements

6x^2+8x+(-8x)=0

We get rid of parentheses

6x^2+8x-8x=0

We add all the numbers together, and all the variables

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$