-8/2y-8=5/y=4-7y=8/y2-16

Solution for -8/2y-8=5/y=4-7y=8/y2-16 equation:

-8/2y-8=5/y=4-7y=8/y2-16

We move all terms to the left:

-8/2y-8-(5/y)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-8/2y-(+5/y)-8=0

We get rid of parentheses

-8/2y-5/y-8=0

We calculate fractions


(-8y)/2y^2+(-10y)/2y^2-8=0

We multiply all the terms by the denominator


(-8y)+(-10y)-8*2y^2=0

Wy multiply elements

-16y^2+(-8y)+(-10y)=0

We get rid of parentheses

-16y^2-8y-10y=0

We add all the numbers together, and all the variables

-16y^2-18y=0

a = -16; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·(-16)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*-16}=\frac{0}{-32}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*-16}=\frac{36}{-32}
=-1+1/8
$