-81+100x2=0

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Solution for -81+100x2=0 equation:



-81+100x^2=0
a = 100; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·100·(-81)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*100}=\frac{-180}{200} =-9/10 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*100}=\frac{180}{200} =9/10 $

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