-82=2(5b-5)-10

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Solution for -82=2(5b-5)-10 equation: 



-82=2(5b-5)-10

We move all terms to the left:

-82-(2(5b-5)-10)=0



We calculate terms in parentheses: -(2(5b-5)-10), so:

2(5b-5)-10

We multiply parentheses

10b-10-10

We add all the numbers together, and all the variables

10b-20

Back to the equation:

-(10b-20)



We get rid of parentheses

-10b+20-82=0

We add all the numbers together, and all the variables

-10b-62=0

We move all terms containing b to the left, all other terms to the right

-10b=62

b=62/-10

b=-6+1/5

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