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-83=5-2(8+6v)
We move all terms to the left:
-83-(5-2(8+6v))=0
We add all the numbers together, and all the variables
-(5-2(6v+8))-83=0
We calculate terms in parentheses: -(5-2(6v+8)), so:We get rid of parentheses
5-2(6v+8)
determiningTheFunctionDomain -2(6v+8)+5
We multiply parentheses
-12v-16+5
We add all the numbers together, and all the variables
-12v-11
Back to the equation:
-(-12v-11)
12v+11-83=0
We add all the numbers together, and all the variables
12v-72=0
We move all terms containing v to the left, all other terms to the right
12v=72
v=72/12
v=6
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