-8=1/3x+x

Solution for -8=1/3x+x equation:

-8=1/3x+x

We move all terms to the left:

-8-(1/3x+x)=0


Domain of the equation: 3x+x)!=0

x∈R


We add all the numbers together, and all the variables

-(+x+1/3x)-8=0

We get rid of parentheses

-x-1/3x-8=0

We multiply all the terms by the denominator


-x*3x-8*3x-1=0

Wy multiply elements

-3x^2-24x-1=0

a = -3; b = -24; c = -1;
Δ = b2-4ac
Δ = -242-4·(-3)·(-1)
Δ = 564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{564}=\sqrt{4*141}=\sqrt{4}*\sqrt{141}=2\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{141}}{2*-3}=\frac{24-2\sqrt{141}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{141}}{2*-3}=\frac{24+2\sqrt{141}}{-6}
$