-8=3(y-4)-7y

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Solution for -8=3(y-4)-7y equation: 



-8=3(y-4)-7y

We move all terms to the left:

-8-(3(y-4)-7y)=0



We calculate terms in parentheses: -(3(y-4)-7y), so:

3(y-4)-7y

We add all the numbers together, and all the variables

-7y+3(y-4)

We multiply parentheses

-7y+3y-12

We add all the numbers together, and all the variables

-4y-12

Back to the equation:

-(-4y-12)



We get rid of parentheses

4y+12-8=0

We add all the numbers together, and all the variables

4y+4=0

We move all terms containing y to the left, all other terms to the right

4y=-4

y=-4/4

y=-1

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