-8a+10=2a(5-4a)

Solution for -8a+10=2a(5-4a) equation:

-8a+10=2a(5-4a)

We move all terms to the left:

-8a+10-(2a(5-4a))=0

We add all the numbers together, and all the variables

-8a-(2a(-4a+5))+10=0


We calculate terms in parentheses: -(2a(-4a+5)), so:

2a(-4a+5)

We multiply parentheses

-8a^2+10a

Back to the equation:

-(-8a^2+10a)


We get rid of parentheses

8a^2-10a-8a+10=0

We add all the numbers together, and all the variables

8a^2-18a+10=0

a = 8; b = -18; c = +10;
Δ = b2-4ac
Δ = -182-4·8·10
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2}{2*8}=\frac{16}{16}
=1
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2}{2*8}=\frac{20}{16}
=1+1/4
$