-8b-12=6(b-1)+8

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Solution for -8b-12=6(b-1)+8 equation:



-8b-12=6(b-1)+8
We move all terms to the left:
-8b-12-(6(b-1)+8)=0
We calculate terms in parentheses: -(6(b-1)+8), so:
6(b-1)+8
We multiply parentheses
6b-6+8
We add all the numbers together, and all the variables
6b+2
Back to the equation:
-(6b+2)
We get rid of parentheses
-8b-6b-2-12=0
We add all the numbers together, and all the variables
-14b-14=0
We move all terms containing b to the left, all other terms to the right
-14b=14
b=14/-14
b=-1

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