-8c-80=(c-3)

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Solution for -8c-80=(c-3) equation: 



-8c-80=(c-3)

We move all terms to the left:

-8c-80-((c-3))=0



We calculate terms in parentheses: -((c-3)), so:

(c-3)

We get rid of parentheses

c-3

Back to the equation:

-(c-3)



We get rid of parentheses

-8c-c+3-80=0

We add all the numbers together, and all the variables

-9c-77=0

We move all terms containing c to the left, all other terms to the right

-9c=77

c=77/-9

c=-8+5/9

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