-8m+4(2m+3)=-6(m+2)+4m

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Solution for -8m+4(2m+3)=-6(m+2)+4m equation: 



-8m+4(2m+3)=-6(m+2)+4m

We move all terms to the left:

-8m+4(2m+3)-(-6(m+2)+4m)=0

We multiply parentheses

-8m+8m-(-6(m+2)+4m)+12=0



We calculate terms in parentheses: -(-6(m+2)+4m), so:

-6(m+2)+4m

We add all the numbers together, and all the variables

4m-6(m+2)

We multiply parentheses

4m-6m-12

We add all the numbers together, and all the variables

-2m-12

Back to the equation:

-(-2m-12)



We add all the numbers together, and all the variables

-(-2m-12)+12=0

We get rid of parentheses

2m+12+12=0

We add all the numbers together, and all the variables

2m+24=0

We move all terms containing m to the left, all other terms to the right

2m=-24

m=-24/2

m=-12

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