-8m+43-5(m-4)=7m-(2m-6)-9m+3

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Solution for -8m+43-5(m-4)=7m-(2m-6)-9m+3 equation: 



-8m+43-5(m-4)=7m-(2m-6)-9m+3

We move all terms to the left:

-8m+43-5(m-4)-(7m-(2m-6)-9m+3)=0

We multiply parentheses

-8m-5m-(7m-(2m-6)-9m+3)+20+43=0



We calculate terms in parentheses: -(7m-(2m-6)-9m+3), so:

7m-(2m-6)-9m+3

We add all the numbers together, and all the variables

-2m-(2m-6)+3

We get rid of parentheses

-2m-2m+6+3

We add all the numbers together, and all the variables

-4m+9

Back to the equation:

-(-4m+9)



We add all the numbers together, and all the variables

-13m-(-4m+9)+63=0

We get rid of parentheses

-13m+4m-9+63=0

We add all the numbers together, and all the variables

-9m+54=0

We move all terms containing m to the left, all other terms to the right

-9m=-54

m=-54/-9

m=+6

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