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-8m^2=-150
We move all terms to the left:
-8m^2-(-150)=0
We add all the numbers together, and all the variables
-8m^2+150=0
a = -8; b = 0; c = +150;
Δ = b2-4ac
Δ = 02-4·(-8)·150
Δ = 4800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4800}=\sqrt{1600*3}=\sqrt{1600}*\sqrt{3}=40\sqrt{3}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{3}}{2*-8}=\frac{0-40\sqrt{3}}{-16} =-\frac{40\sqrt{3}}{-16} =-\frac{5\sqrt{3}}{-2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{3}}{2*-8}=\frac{0+40\sqrt{3}}{-16} =\frac{40\sqrt{3}}{-16} =\frac{5\sqrt{3}}{-2} $
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