-8t-10+14t=2(t+2)-5

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Solution for -8t-10+14t=2(t+2)-5 equation:



-8t-10+14t=2(t+2)-5
We move all terms to the left:
-8t-10+14t-(2(t+2)-5)=0
We add all the numbers together, and all the variables
6t-(2(t+2)-5)-10=0
We calculate terms in parentheses: -(2(t+2)-5), so:
2(t+2)-5
We multiply parentheses
2t+4-5
We add all the numbers together, and all the variables
2t-1
Back to the equation:
-(2t-1)
We get rid of parentheses
6t-2t+1-10=0
We add all the numbers together, and all the variables
4t-9=0
We move all terms containing t to the left, all other terms to the right
4t=9
t=9/4
t=2+1/4

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