-8v(6v+7)=0

Solution for -8v(6v+7)=0 equation:

-8v(6v+7)=0

We multiply parentheses

-48v^2-56v=0

a = -48; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·(-48)·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*-48}=\frac{0}{-96}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*-48}=\frac{112}{-96}
=-1+1/6
$