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-8w^2-13w+6=0
a = -8; b = -13; c = +6;
Δ = b2-4ac
Δ = -132-4·(-8)·6
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-19}{2*-8}=\frac{-6}{-16} =3/8 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+19}{2*-8}=\frac{32}{-16} =-2 $
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