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-8x(-2x-3)=6-x
We move all terms to the left:
-8x(-2x-3)-(6-x)=0
We add all the numbers together, and all the variables
-8x(-2x-3)-(-1x+6)=0
We multiply parentheses
16x^2+24x-(-1x+6)=0
We get rid of parentheses
16x^2+24x+1x-6=0
We add all the numbers together, and all the variables
16x^2+25x-6=0
a = 16; b = 25; c = -6;
Δ = b2-4ac
Δ = 252-4·16·(-6)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1009}}{2*16}=\frac{-25-\sqrt{1009}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1009}}{2*16}=\frac{-25+\sqrt{1009}}{32} $
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