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-8x(5x-3)=0
We multiply parentheses
-40x^2+24x=0
a = -40; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-40)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-40}=\frac{-48}{-80} =3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-40}=\frac{0}{-80} =0 $
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