-8x(8x-8)=0

Solution for -8x(8x-8)=0 equation:

-8x(8x-8)=0

We multiply parentheses

-64x^2+64x=0

a = -64; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·(-64)·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*-64}=\frac{-128}{-128}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*-64}=\frac{0}{-128}
=0
$