-8x(x+1)-7=-5(x-4)

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Solution for -8x(x+1)-7=-5(x-4) equation: 



-8x(x+1)-7=-5(x-4)

We move all terms to the left:

-8x(x+1)-7-(-5(x-4))=0

We multiply parentheses

-8x^2-8x-(-5(x-4))-7=0



We calculate terms in parentheses: -(-5(x-4)), so:

-5(x-4)

We multiply parentheses

-5x+20

Back to the equation:

-(-5x+20)



We get rid of parentheses

-8x^2-8x+5x-20-7=0

We add all the numbers together, and all the variables

-8x^2-3x-27=0

a = -8; b = -3; c = -27;
Δ = b2-4ac
Δ = -32-4·(-8)·(-27)
Δ = -855
Delta is less than zero, so there is no solution for the equation

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