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-8x(x+2)+2x+7=7x+9
We move all terms to the left:
-8x(x+2)+2x+7-(7x+9)=0
We add all the numbers together, and all the variables
2x-8x(x+2)-(7x+9)+7=0
We multiply parentheses
-8x^2+2x-16x-(7x+9)+7=0
We get rid of parentheses
-8x^2+2x-16x-7x-9+7=0
We add all the numbers together, and all the variables
-8x^2-21x-2=0
a = -8; b = -21; c = -2;
Δ = b2-4ac
Δ = -212-4·(-8)·(-2)
Δ = 377
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{377}}{2*-8}=\frac{21-\sqrt{377}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{377}}{2*-8}=\frac{21+\sqrt{377}}{-16} $
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