-8x(x+6)=5x+2(x-4)

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Solution for -8x(x+6)=5x+2(x-4) equation:



-8x(x+6)=5x+2(x-4)
We move all terms to the left:
-8x(x+6)-(5x+2(x-4))=0
We multiply parentheses
-8x^2-48x-(5x+2(x-4))=0
We calculate terms in parentheses: -(5x+2(x-4)), so:
5x+2(x-4)
We multiply parentheses
5x+2x-8
We add all the numbers together, and all the variables
7x-8
Back to the equation:
-(7x-8)
We get rid of parentheses
-8x^2-48x-7x+8=0
We add all the numbers together, and all the variables
-8x^2-55x+8=0
a = -8; b = -55; c = +8;
Δ = b2-4ac
Δ = -552-4·(-8)·8
Δ = 3281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{3281}}{2*-8}=\frac{55-\sqrt{3281}}{-16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{3281}}{2*-8}=\frac{55+\sqrt{3281}}{-16} $

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