-8x+1/4(20x-12)=10x-13x-3

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Solution for -8x+1/4(20x-12)=10x-13x-3 equation: 



-8x+1/4(20x-12)=10x-13x-3

We move all terms to the left:

-8x+1/4(20x-12)-(10x-13x-3)=0



Domain of the equation: 4(20x-12)!=0

x∈R



We add all the numbers together, and all the variables

-8x+1/4(20x-12)-(-3x-3)=0

We get rid of parentheses

-8x+1/4(20x-12)+3x+3=0

We multiply all the terms by the denominator


-8x*4(20x-12)+3x*4(20x-12)+3*4(20x-12)+1=0

Wy multiply elements

-32x^2(2+12x^2(2+12x(2+1=0

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