-8x+1/4(20x-12)=3x-13x-3

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Solution for -8x+1/4(20x-12)=3x-13x-3 equation:



-8x+1/4(20x-12)=3x-13x-3
We move all terms to the left:
-8x+1/4(20x-12)-(3x-13x-3)=0
Domain of the equation: 4(20x-12)!=0
x∈R
We add all the numbers together, and all the variables
-8x+1/4(20x-12)-(-10x-3)=0
We get rid of parentheses
-8x+1/4(20x-12)+10x+3=0
We multiply all the terms by the denominator
-8x*4(20x-12)+10x*4(20x-12)+3*4(20x-12)+1=0
Wy multiply elements
-32x^2(2+40x^2(2+12x(2+1=0

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