-8x+5-4(x-1)=-4x(7x-4)+4

Solution for -8x+5-4(x-1)=-4x(7x-4)+4 equation:

-8x+5-4(x-1)=-4x(7x-4)+4

We move all terms to the left:

-8x+5-4(x-1)-(-4x(7x-4)+4)=0

We multiply parentheses

-8x-4x-(-4x(7x-4)+4)+4+5=0


We calculate terms in parentheses: -(-4x(7x-4)+4), so:

-4x(7x-4)+4

We multiply parentheses

-28x^2+16x+4

Back to the equation:

-(-28x^2+16x+4)


We add all the numbers together, and all the variables

-(-28x^2+16x+4)-12x+9=0

We get rid of parentheses

28x^2-16x-12x-4+9=0

We add all the numbers together, and all the variables

28x^2-28x+5=0

a = 28; b = -28; c = +5;
Δ = b2-4ac
Δ = -282-4·28·5
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{14}}{2*28}=\frac{28-4\sqrt{14}}{56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{14}}{2*28}=\frac{28+4\sqrt{14}}{56}
$