-8x+7(10x-11)=2(-3x-6)+3

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Solution for -8x+7(10x-11)=2(-3x-6)+3 equation:



-8x+7(10x-11)=2(-3x-6)+3
We move all terms to the left:
-8x+7(10x-11)-(2(-3x-6)+3)=0
We multiply parentheses
-8x+70x-(2(-3x-6)+3)-77=0
We calculate terms in parentheses: -(2(-3x-6)+3), so:
2(-3x-6)+3
We multiply parentheses
-6x-12+3
We add all the numbers together, and all the variables
-6x-9
Back to the equation:
-(-6x-9)
We add all the numbers together, and all the variables
62x-(-6x-9)-77=0
We get rid of parentheses
62x+6x+9-77=0
We add all the numbers together, and all the variables
68x-68=0
We move all terms containing x to the left, all other terms to the right
68x=68
x=68/68
x=1

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