-8x+7(10x-11)=2(-3x-6)+3

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Solution for -8x+7(10x-11)=2(-3x-6)+3 equation: 



-8x+7(10x-11)=2(-3x-6)+3

We move all terms to the left:

-8x+7(10x-11)-(2(-3x-6)+3)=0

We multiply parentheses

-8x+70x-(2(-3x-6)+3)-77=0



We calculate terms in parentheses: -(2(-3x-6)+3), so:

2(-3x-6)+3

We multiply parentheses

-6x-12+3

We add all the numbers together, and all the variables

-6x-9

Back to the equation:

-(-6x-9)



We add all the numbers together, and all the variables

62x-(-6x-9)-77=0

We get rid of parentheses

62x+6x+9-77=0

We add all the numbers together, and all the variables

68x-68=0

We move all terms containing x to the left, all other terms to the right

68x=68

x=68/68

x=1

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