-8x-8+3(x-2)=-3x2

Solution for -8x-8+3(x-2)=-3x2 equation:

-8x-8+3(x-2)=-3x^2

We move all terms to the left:

-8x-8+3(x-2)-(-3x^2)=0

We multiply parentheses

-(-3x^2)-8x+3x-6-8=0

We get rid of parentheses

3x^2-8x+3x-6-8=0

We add all the numbers together, and all the variables

3x^2-5x-14=0

a = 3; b = -5; c = -14;
Δ = b2-4ac
Δ = -52-4·3·(-14)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{193}}{2*3}=\frac{5-\sqrt{193}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{193}}{2*3}=\frac{5+\sqrt{193}}{6}
$